CN102553943A - Method for controlling helper rolls of loop for carbon steel continuous annealing unit - Google Patents

Abstract

The invention provides a method for controlling helper rolls of a loop for a carbon steel continuous annealing unit, which includes steps of 1), receiving data of the loop; 2), computing tension loss caused by inherent inertia of each helper roll according to the data received in the step 1); 3), zoning the helper rolls of the loop so that each zone comprises one driving roll and a non-driving roll close to the same; and 4), computing compensation torques which are used for compensating affection to tension caused by inertia of all helper rolls, steels trip inertia and inherent inertia of a motor of the driving roll and are required on a motor shaft of the driving roll within each zone, and then applying the three types of compensating torques for execution of the motor of the driving roll within the zone. The helper rolls are zoned as units, and various tension losses within different zones are computed and can be compensated by the driving rolls within the zones, so that affection to tension, caused by the length of the steel strip and the mechanical inertia of the loop, can be reduced.

Description

A kind ofly be used for the control method that carbon steel connects the kink help roll move back unit

Technical field

The invention belongs to cold rolling continuous processing line field, be specifically related to a kind of control method that carbon steel connects the kink help roll that moves back unit that is used for.

Background technology

In the cold rolling continuous processing line unit process function generally be the uncoiling of stock roll elder generation, weld with the band steel that moves ahead after, get into process section and handle, PROCESS FOR TREATMENT is accomplished the back and is cut at outlet section and be rolled into finished product by coiling machine and roll up.The processing of process section generally has technologies such as pickling, annealing, zinc-plated, zinc-plated, degreasing, color coating.In the production process of cold rolling continuous processing line, for quality and the output that guarantees cold-rolled products, the speed of service of technology section strip steel should keep stablizing constant as far as possible, to satisfy the production technology of cold-rolling treatment product.And entrance is because there are conversion operation process such as uncoiling, crop, back-end crop and welding in stock roll; Can't remain consistent speed running with process section; Therefore an entry loop is set between entrance and process section; Be used to store a certain amount of band steel, can not cause process section to stop or reduction of speed with the conversion operation that guarantees inlet.Equally, outlet section also is provided with an outlet kink that plays same purpose owing to exist and the conversion operation process such as to cut, take a sample, to batch between outlet section and process section.

One of target of cold rolling processing line unit is to guarantee that production process is continuous uninterrupted all the time.Need adopt the relevant equipment of kink for this reason.With kink as the inlet region, the buffering between process island and the outlet area.These bufferings can make the band steel in the regular hour amount, keep the continuous operation of producing.For example: for the inlet region kink, be filled the band steel of certain cover amount when beginning to go up volume, if a new coil of strip is put into inlet (entrance velocity=0), this kink can make process section continue operation; For the outlet area kink, by emptying, carrying out between coil of strip conversion operational period during beginning, this kink can absorb the band steel from process section.Kink can be understood as the assembly pulley of weight for the band steel abstractively.

Kink is divided into vertical loop and horizontal loop according to installation.Vertical loop is as shown in Figure 1, and its integral body moves up and down through looping car (kink moves framework) and moves realization.Looping car is through rope traction, and the convergent-divergent of steel wire rope is reeled through winding drum and realized, thereby the kink main driving motor is realized moving up and down of looping car through the coiling action of gear-box control winding drum, and then control kink cover amount.Bottom or top at kink also have a series of fixing roller to be, are help roll, are divided into live-roller and non-live-roller.

The Position Control of kink and Tension Control mainly realize through the main driving motor of control kink.But at kink between moving period, or,, must accurately control live-roller in order to be reduced to a minimum of the influence of the machinery inertial of band steel length (weight) or kink to the tension force performance in the kink accelerating period.

Summary of the invention

The technical problem that the present invention will solve is: a kind of control method that carbon steel connects the kink help roll that moves back unit that is used for is provided, can the moment of live-roller motor be compensated, to reduce the influence to the tension force performance of band steel length and kink machinery inertial.

The present invention solves the problems of the technologies described above the technical scheme of being taked to be: a kind ofly be used for the control method that carbon steel connects the kink help roll move back unit, it is characterized in that: it may further comprise the steps:

1) receives the kink data, comprising: kink number of plies Nr_Loops, band steel density Spec_Weight, belt steel thickness Strip_Thickness, strip width Strip_Width, kink entrance velocity V_In, the entry accelerated degree of kink A_In, kink muzzle velocity V_Out, kink outlet acceleration A _ Out and kink physical location S_act;

The loss of tension that the intrinsic inertia of each help roll of data computation that 2) receives according to step 1) causes;

3) the kink help roll is carried out subregion, each subregion comprises a live-roller and near the non-live-roller of this live-roller;

4) in each subregion, calculate the influence that causes for inertia, band steel inertia and the intrinsic inertia of live-roller motor that compensates by all help rolls, institute's compensating torque of needs respectively on the live-roller motor shaft to the tension force performance; Carry out to the live-roller motor in this subregion above-mentioned three kinds of compensating torques are additional.

Press such scheme, said step 2) concrete computational process be: the acceleration that calculates single help roll earlier:

$A\_\mathrm{Roll}=A\_\mathrm{In}+(A\_\mathrm{Out}-A\_\mathrm{In})\×\frac{\mathrm{Position}\_\mathrm{Roll}}{\mathrm{Nr}\_\mathrm{Loops}}[m/s^2]---\left(2\right)$

In the formula, A_Roll is the acceleration of help roll; A_In is the entry accelerated degree of kink; A_Out is a kink outlet acceleration; Nr_Loops is the kink number of plies; Position_Roll is the positional value of help roll, can be roller 0,1,2,3

The loss of tension that the intrinsic inertia of single help roll causes is:

$T\_\mathrm{Inertia}=\frac{J\×4\×A\_\mathrm{Roll}}{D^2}\left[N\right]---\left(3\right)$

In the formula, the loss of tension that T_Inertia causes for the intrinsic inertia by help roll; J is the inertia of roller; A_Roll is the acceleration of help roll; D is the diameter of help roll.

Press such scheme, said step 4) by the loss of tension that the inertia of all help rolls in the subregion causes promptly to the influence of tension force performance is:

$T\_\mathrm{In}\_\mathrm{zone}=\frac{T\_\mathrm{In}\_\mathrm{<figure-callout\; id="1"\; label="R"\; filenames="HDA0000130594550000012.png"\; state="\{\{state\}\}">R</figure-callout>}1}{2}+T\_\mathrm{In}\_\mathrm{<figure-callout\; id="2"\; label="R"\; filenames="HDA0000130594550000012.png"\; state="\{\{state\}\}">R</figure-callout>}2+T\_\mathrm{In}\_\mathrm{<figure-callout\; id="3"\; label="R"\; filenames="HDA0000130594550000012.png"\; state="\{\{state\}\}">R</figure-callout>}3+L+\frac{T\_\mathrm{In}\_\mathrm{Rlast}}{2}\left[N\right]---\left(4\right)$

In the formula, the loss of tension that T_In_zone causes for the inertia by all help rolls in the subregion; The loss of tension that T_In_Rn causes for the inertia by n help roll in the subregion, T_In_Rn is obtained by formula 3.

Press such scheme, the loss of tension that said step 4) is caused by the band steel inertia in the subregion promptly influences and is: T_lose=Nr_Loops_Zn * S_act * Spec_Weight * S_Width * S_Thick * A_average_Zn [N] (5)

In the formula, the loss of tension of T_lose for causing by band steel inertia in the n subregion; Nr_Loops_Zn is the number of plies of kink in the n subregion; S_act is the physical location of kink; Spec_Weight is the density of band steel; S_Width is the width of band steel; S_Thick is the thickness of band steel; A_average_Zn is the average acceleration of band steel in the n subregion, by computes:

$A\_\mathrm{aversge}\_\mathrm{Zn}=\frac{A\_\mathrm{First}\_\mathrm{Roll}\_\mathrm{Zn}+A\_\mathrm{Last}\_\mathrm{Roll}\_\mathrm{Zn}}{2}---\left(6\right),$

In the formula, A_average_Zn is the average acceleration of band steel in the n subregion; A_First_Roll_Zn is the acceleration of the 1st help roll in the n subregion, and use formula 2 is calculated; A_Last_Roll_Zn is the acceleration of last 1 help roll in the n subregion, and use formula 2 is calculated.

Press such scheme, the loss of tension that said step 4) is caused by the inertia of all help rolls in the subregion promptly influences the compensating torque of needs on the live-roller motor shaft that causes and is:

$\mathrm{TQ}\_\mathrm{Inertia}\_\mathrm{Roll}\_\mathrm{Zn}=\frac{T\_\mathrm{Inertia}\_\mathrm{Roll}\_\mathrm{Zn}\&times;\mathrm{<figure-callout\; id="2"\; label="D"\; filenames="HDA0000130594550000012.png"\; state="\{\{state\}\}">D</figure-callout>}}{2\&times;i}[N\&CenterDot;m]---\left(7\right),$

In the formula, TQ_Inertia_Roll_Zn is in the n subregion, for compensation 4 losses of tension that cause, needed compensating torque on the live-roller motor shaft; The loss of tension that T_Inertia_Roll_Zn causes for the inertia by all help rolls in the n subregion, use formula 4 is calculated; D is the diameter of band transmission help roll; I is a speed reducing ratio.

Press such scheme, the loss of tension that said step 4) is caused by the band steel inertia in the subregion promptly influences the compensating torque of needs on the live-roller motor shaft that causes and is:

$\mathrm{TQ}\_\mathrm{Inertia}\_\mathrm{Strip}\_\mathrm{Zn}=\frac{T\_\mathrm{Inertia}\_\mathrm{Strip}\_\mathrm{Zn}\&times;\mathrm{<figure-callout\; id="2"\; label="D"\; filenames="HDA0000130594550000012.png"\; state="\{\{state\}\}">D</figure-callout>}}{2\&times;i}[N\&CenterDot;m]---\left(8\right),$

In the formula, TQ_Inertia_Strip_Zn is in the n subregion, for compensation 5 losses of tension that cause, needed compensating torque on the live-roller motor shaft; The loss of tension of T_Inertia_Strip_Zn for causing by band steel inertia in the n subregion, use formula 5 is calculated; D is the diameter of band transmission help roll; I is a speed reducing ratio.

Press such scheme, the loss of tension that said step 4) is caused by the intrinsic inertia of live-roller motor in the subregion promptly influences the compensating torque of needs on the live-roller motor shaft that causes and is:

$\mathrm{TQ}\_\mathrm{Inertia}\_\mathrm{Mot}\_\mathrm{Zn}=J\_\mathrm{Mot}\&times;\frac{2\&times;A+\mathrm{Roll}\&times;i}{\mathrm{Diam}}[N\&CenterDot;m]---\left(9\right),$

In the formula, the compensating torque of TQ_Inertia_Mot_Zn in the n subregion, causing by the intrinsic inertia of live-roller motor; J_Mot is the intrinsic inertia of live-roller motor; A_Roll is the acceleration of live-roller, and use formula 2 is calculated; Diam is the diameter of motor shaft; I is a speed reducing ratio.

Beneficial effect of the present invention is:

1, because the help roll in kink is divided into live-roller and non-live-roller; Inertia loss on non-live-roller can't replenish through self; Have only through nearest live-roller and compensate; Designed subregion for this reason and handled this problem, the division of subregion is divided according to live-roller, and each subregion is made up of live-roller and near non-live-roller.With the subregion is unit, calculates the various losses of tension in each subregion, remedies these loss of tension through the live-roller torque compensation in the subregion then, to reduce the influence to the tension force performance of band steel length and kink machinery inertial.

Description of drawings

Fig. 1 is the sketch map of vertical loop.

Fig. 2 is the division sketch map of vertical loop subregion.

Fig. 3 is the control block diagram of live-roller motor in the arbitrary subregion of vertical loop.

The specific embodiment

The control block diagram of live-roller motor is as shown in Figure 3 in the arbitrary subregion of vertical loop, and the control core of live-roller motor is speed regulator and torque adjusting device, and the effect of speed regulator is the speed of regulating motor, makes the speed of motor reach the motor speed setting value.The effect of torque adjusting device is the output of accepting speed regulator, and it is given to form moment behind other torque compensations that superpose simultaneously, makes motor export corresponding moment through adjuster.

Being used for the control method that carbon steel connects the kink help roll move back unit may further comprise the steps:

1) receives the kink data, comprising: kink number of plies Nr_Loops, band steel density Spec_Weight, belt steel thickness Strip_Thickness, strip width Strip_Width, kink entrance velocity V_In, the entry accelerated degree of kink A_In, kink muzzle velocity V_Out, kink outlet acceleration A _ Out and kink physical location S_act.Use these data, all rollers in the kink are done some calculating.

The loss of tension that the intrinsic inertia of each help roll of data computation that 2) receives according to step 1) causes.

For each help roll (transmission or non-transmission), all will carry out following calculating.These result calculated are ephemeral data, and the help roll that these ephemeral datas will be used for after a while calculates.

Help roll has the loss of tension.In addition, the speed of help roll or acceleration are influential to the calculating of band steel inertia.

Speed calculation:

$V\_\mathrm{Roll}=V\_\mathrm{In}+(V\_\mathrm{Out}-V\_\mathrm{In})\&times;\frac{\mathrm{Position}\_\mathrm{Roll}}{\mathrm{Nr}\_\mathrm{Loops}}[m/s]---\left(1\right)$

In the formula, V_Roll is the speed of help roll; V_In is the kink entrance velocity; V_Out is the kink muzzle velocity; Nr_Loops is the number of plies of kink; Position_Roll is the positional value of help roll, can be roller 0,1,2,3 ...

The acceleration of help roll:

$A\_\mathrm{Roll}=A\_\mathrm{In}+(A\_\mathrm{Out}-A\_\mathrm{In})\&times;\frac{\mathrm{Position}\_\mathrm{Roll}}{\mathrm{Nr}\_\mathrm{Loops}}[m/s^2]---\left(2\right)$

In the formula, A_Roll is the acceleration of help roll; A_In is the entry accelerated degree of kink; A_Out is a kink outlet acceleration; Nr_Loops is the number of plies of kink; Position_Roll is the positional value of help roll, can be roller 0,1,2,3

The loss of tension that the intrinsic inertia of help roll causes is:

$T\_\mathrm{Inertia}=\frac{J\&times;4\&times;A\_\mathrm{Roll}}{D^2}\left[N\right]---\left(3\right)$

In the formula, the loss of tension that T_Inertia causes for the intrinsic inertia by help roll; J is the inertia of help roll; A_Roll is the acceleration of help roll; D is the diameter of help roll.

3) the kink help roll is carried out subregion, each subregion comprises a live-roller and near the non-live-roller of this live-roller.Fig. 2 is the division sketch map of the vertical loop subregion of belt drive roller, and present embodiment comprises 7 help rolls, wherein is numbered 2,4 and is live-roller, is numbered 0,1,3,5,6 and is non-live-roller.This kink is divided into two subregions: the 1st subregion and the 2nd subregion.Comprise help roll in the 1st subregion 0,1,2, No. 3, the loss of local area internal tension realizes through the transmission device of No. 2 help rolls of compensation.Comprise help roll in the 2nd subregion 3,4,5, No. 6, the loss of local area internal tension realizes through the transmission device of No. 4 help rolls of compensation.No. 3 help roll had both belonged to the 1st subregion, also belonged to the 2nd subregion, and the loss of tension that on No. 3 help rolls, causes is divided the 1st subregion and the 2nd subregion equally.

4) in each subregion, calculate the influence that causes for inertia, band steel inertia and the intrinsic inertia of live-roller motor that compensates by all help rolls, institute's compensating torque of needs respectively on the live-roller motor shaft to the tension force performance; Carry out to the live-roller motor in this subregion above-mentioned three kinds of compensating torques are additional.

The loss of tension by the inertia of single help roll (the band grade of steel is other) causes is calculated with formula 3.

The loss of tension by the inertia of all help rolls in the definition (the band grade of steel is other) causes is calculated with formula 4:

$T\_\mathrm{In}\_\mathrm{zone}=\frac{T\_\mathrm{In}\_\mathrm{<figure-callout\; id="1"\; label="R"\; filenames="HDA0000130594550000012.png"\; state="\{\{state\}\}">R</figure-callout>}1}{2}+T\_\mathrm{In}\_\mathrm{<figure-callout\; id="2"\; label="R"\; filenames="HDA0000130594550000012.png"\; state="\{\{state\}\}">R</figure-callout>}2+T\_\mathrm{In}\_\mathrm{<figure-callout\; id="3"\; label="R"\; filenames="HDA0000130594550000012.png"\; state="\{\{state\}\}">R</figure-callout>}3+L+\frac{T\_\mathrm{In}\_\mathrm{Rlast}}{2}\left[N\right]---\left(4\right)$

In the formula, the loss of tension that T_In_zone causes for the inertia by all help rolls in the subregion (the band grade of steel is other); The loss of tension that T_In_Rn causes for the inertia by n help roll in the subregion (the band grade of steel is other), the computing formula of T_In_Rn is seen formula 3.

The loss of tension that is caused by the band steel inertia in the definition is:

T_lose＝Nr_Loops_Zn×S_act×Spec_Weight×S_Width×S_Thick×A_average_Zn[N](5)

In the formula, the loss of tension of T_lose for causing by band steel inertia in the definition; Nr_Loops_Zn is the number of plies of kink in the n subregion; S_act is the physical location of kink; Spec_Weight is the density of band steel; S_Width is the width of band steel; S_Thick is the thickness of band steel; A_average_Zn is the average acceleration of band steel in the n subregion, by computes:

$A\_\mathrm{aversge}\_\mathrm{Zn}=\frac{A\_\mathrm{First}\_\mathrm{Roll}\_\mathrm{Zn}+A\_\mathrm{Last}\_\mathrm{Roll}\_\mathrm{Zn}}{2}---\left(6\right),$

In the formula, A_average_Zn is the average acceleration of band steel in the n subregion; A_First_Roll_Zn is the acceleration of the 1st help roll in the n subregion, and use formula 2 is calculated; A_Last_Roll_Zn is the acceleration of last 1 help roll in the n subregion, and use formula 2 is calculated.

In the n subregion, for compensation 4 and formula 5 said two kinds of losses of tension to the influence of tension force performance, needed compensating torque is on the live-roller motor shaft:

$\mathrm{TQ}\_\mathrm{Inertia}\_\mathrm{Roll}\_\mathrm{Zn}=\frac{T\_\mathrm{Inertia}\_\mathrm{Roll}\_\mathrm{Zn}\&times;\mathrm{<figure-callout\; id="2"\; label="D"\; filenames="HDA0000130594550000012.png"\; state="\{\{state\}\}">D</figure-callout>}}{2\&times;i}[N\&CenterDot;m]---\left(7\right),$

$\mathrm{TQ}\_\mathrm{Inertia}\_\mathrm{Strip}\_\mathrm{Zn}=\frac{T\_\mathrm{Inertia}\_\mathrm{Strip}\_\mathrm{Zn}\&times;\mathrm{<figure-callout\; id="2"\; label="D"\; filenames="HDA0000130594550000012.png"\; state="\{\{state\}\}">D</figure-callout>}}{2\&times;i}[N\&CenterDot;m]---\left(8\right),$

In the formula, TQ_Inertia_Roll_Zn is in the n subregion, for compensation 4 losses of tension that cause, needed compensating torque on the live-roller motor shaft; TQ_Inertia_Strip_Zn is in the n subregion, for compensation 5 losses of tension that cause, needed compensating torque on the live-roller motor shaft; The loss of tension that T_Inertia_Roll_Zn causes for the inertia by all help rolls in the n subregion (the band grade of steel is other), use formula 4 is calculated; The loss of tension of T_Inertia_Strip_Zn for causing by band steel inertia in the n subregion, use formula 5 is calculated; D is the diameter of band transmission help roll; I is a speed reducing ratio.

In the n subregion, in order to compensate the influence of the intrinsic inertia of live-roller motor to the tension force performance, needed compensating torque is on the live-roller motor shaft:

$\mathrm{TQ}\_\mathrm{Inertia}\_\mathrm{Mot}\_\mathrm{Zn}=J\_\mathrm{Mot}\&times;\frac{2\&times;A+\mathrm{Roll}\&times;i}{\mathrm{Diam}}[N\&CenterDot;m]---\left(9\right),$

In the formula, the compensating torque of TQ_Inertia_Mot_Zn in the n subregion, causing by the intrinsic inertia of live-roller motor; J_Mot is the intrinsic inertia of live-roller motor; A_Roll is the acceleration of live-roller, and use formula 2 is calculated; Diam is the diameter of motor shaft; I is a speed reducing ratio.

Claims (7)

1. one kind is used for the control method that carbon steel connects the kink help roll that moves back unit, and it is characterized in that: it may further comprise the steps:

1) receives the kink data, comprising: kink number of plies Nr_Loops, band steel density Spec_Weight, belt steel thickness Strip_Thickness, strip width Strip_Width, kink entrance velocity V_In, the entry accelerated degree of kink A_In, kink muzzle velocity V_Out, kink outlet acceleration A _ Out and kink physical location S_act;

The loss of tension that the intrinsic inertia of each help roll of data computation that 2) receives according to step 1) causes;

3) the kink help roll is carried out subregion, each subregion comprises a live-roller and near the non-live-roller of this live-roller;

4) in each subregion, calculate the influence that causes for inertia, band steel inertia and the intrinsic inertia of live-roller motor that compensates by all help rolls, institute's compensating torque of needs respectively on the live-roller motor shaft to the tension force performance; Carry out to the live-roller motor in this subregion above-mentioned three kinds of compensating torques are additional.

2. according to claim 1ly be used for the control method that carbon steel connects the kink help roll move back unit, it is characterized in that: concrete computational process said step 2) is: the acceleration that calculates single help roll earlier:

$A\_\mathrm{Roll}=A\_\mathrm{In}+(A\_\mathrm{Out}-A\_\mathrm{In})\&times;\frac{\mathrm{Position}\_\mathrm{Roll}}{\mathrm{Nr}\_\mathrm{Loops}}[m/s^2]---\left(2\right),$

In the formula, A_Roll is the acceleration of help roll; A_In is the entry accelerated degree of kink; A_Out is a kink outlet acceleration; Nr_Loops is the kink number of plies; Position_Roll is the positional value of help roll, can be roller 0,1,2,3

The loss of tension that the intrinsic inertia of single help roll causes is:

$T\_\mathrm{Inertia}=\frac{J\&times;4\&times;A\_\mathrm{Roll}}{D^2}\left[N\right]---\left(3\right),$

In the formula, the loss of tension that T_Inertia causes for the intrinsic inertia by help roll; J is the inertia of help roll; A_Roll is the acceleration of help roll; D is the diameter of help roll.

3. according to claim 2ly be used for the control method that carbon steel connects the kink help roll move back unit, it is characterized in that: said step 4) by the loss of tension that the inertia of all help rolls in the subregion causes promptly to the influence of tension force performance is:

$T\_\mathrm{In}\_\mathrm{zone}=\frac{T\_\mathrm{In}\_R1}{2}+T\_\mathrm{In}\_R2+T\_\mathrm{In}\_R3+L+\frac{T\_\mathrm{In}\_\mathrm{Rlast}}{2}\left[N\right]---\left(4\right),$

In the formula, the loss of tension that T_In_zone causes for the inertia by all help rolls in the subregion; The loss of tension that T_In_Rn causes for the inertia by n help roll in the subregion, T_In_Rn is obtained by formula 3.

4. according to claim 2ly be used for the control method that carbon steel connects the kink help roll move back unit, it is characterized in that: said step 4) by the loss of tension that the band steel inertia in the subregion causes promptly to the influence of tension force performance is:

T_lose＝Nr_Loops_Zn×S_act×Spec_Weight×S_Width×S_Thick×A_average_Zn[N](5)

In the formula, the loss of tension of T_lose for causing by band steel inertia in the definition; Nr_Loops_Zn is the number of plies of kink in the n subregion; S_act is the physical location of kink; Spec_Weight is the density of band steel; S_Width is the width of band steel; S_Thick is the thickness of band steel; A_average_Zn is the average acceleration of band steel in the n subregion, by computes:

$A\_\mathrm{aversge}\_\mathrm{Zn}=\frac{A\_\mathrm{First}\_\mathrm{Roll}\_\mathrm{Zn}+A\_\mathrm{Last}\_\mathrm{Roll}\_\mathrm{Zn}}{2}---\left(6\right),$

In the formula, A_average_Zn is the average acceleration of band steel in the n subregion; A_First_Roll_Zn is the acceleration of the 1st help roll in the n subregion, and use formula 2 is calculated; A_Last_Roll_Zn is the acceleration of last 1 help roll in the n subregion, and use formula 2 is calculated.

5. according to claim 3ly be used for the control method that carbon steel connects the kink help roll move back unit, it is characterized in that: the loss of tension that said step 4) is caused by the inertia of all help rolls in the subregion promptly influences the compensating torque of needs on the live-roller motor shaft that causes and is:

$\mathrm{TQ}\_\mathrm{Inertia}\_\mathrm{Roll}\_\mathrm{Zn}=\frac{T\_\mathrm{Inertia}\_\mathrm{Roll}\_\mathrm{Zn}\&times;D}{2\&times;i}[N\&CenterDot;m]---\left(7\right),$

In the formula, TQ_Inertia_Roll_Zn is in the n subregion, for compensation 4 losses of tension that cause, needed compensating torque on the live-roller motor shaft; The loss of tension that T_Inertia_Roll_Zn causes for the inertia by all help rolls in the n subregion, use formula 4 is calculated; D is the diameter of band transmission help roll; I is a speed reducing ratio.

6. according to claim 4ly be used for the control method that carbon steel connects the kink help roll move back unit, it is characterized in that: the loss of tension that said step 4) is caused by the band steel inertia in the subregion promptly influences the compensating torque of needs on the live-roller motor shaft that causes and is:

$\mathrm{TQ}\_\mathrm{Inertia}\_\mathrm{Strip}\_\mathrm{Zn}=\frac{T\_\mathrm{Inertia}\_\mathrm{Strip}\_\mathrm{Zn}\&times;D}{2\&times;i}[N\&CenterDot;m]---\left(8\right),$

In the formula, TQ_Inertia_Strip_Zn is in the n subregion, for compensation 5 losses of tension that cause, needed compensating torque on the live-roller motor shaft; The loss of tension of T_Inertia_Strip_Zn for causing by band steel inertia in the n subregion, use formula 5 is calculated; D is the diameter of band transmission help roll; I is a speed reducing ratio.

7. according to claim 2ly be used for the control method that carbon steel connects the kink help roll move back unit, it is characterized in that: the loss of tension that said step 4) is caused by the intrinsic inertia of live-roller motor in the subregion promptly influences the compensating torque of needs on the live-roller motor shaft that causes and is:

$\mathrm{TQ}\_\mathrm{Inertia}\_\mathrm{Mot}\_\mathrm{Zn}=J\_\mathrm{Mot}\&times;\frac{2\&times;A+\mathrm{Roll}\&times;i}{\mathrm{Diam}}[N\&CenterDot;m]---\left(9\right),$

In the formula, the compensating torque of TQ_Inertia_Mot_Zn in the n subregion, causing by the intrinsic inertia of live-roller motor; J_Mot is the intrinsic inertia of live-roller motor; A_Roll is the acceleration of live-roller, and use formula 2 is calculated; Diam is the diameter of motor shaft; I is a speed reducing ratio.

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